X^2+x+2+3x^2+6x=2

Solution for X^2+x+2+3x^2+6x=2 equation:

X^2+X+2+3X^2+6X=2

We move all terms to the left:

X^2+X+2+3X^2+6X-(2)=0

We add all the numbers together, and all the variables

4X^2+7X=0

a = 4; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·4·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*4}=\frac{-14}{8}
=-1+3/4
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*4}=\frac{0}{8}
=0
$